主題: 問題

[gcobt44292]

#include<stdio.h>
#include<stdlib.h>
#define size 20
size_t getsize(float *ptr);
int main(void)
{
float array[size];
printf("the number of bytes in the array is %u""\nthe number of bytes returned bt getsize is %u\n",sizeof(array),getsize(array));
}//end main
size_t getsize(float *ptr)
{
return sizeof(ptr);
}
運算出來the number of bytes in the array is 80為什麼, float為啥是4  float array[size]--4*20

另外%p是將16禁制列印出來?

[Yamaka]

#include<stdio.h>
#include<stdlib.h>
#define size 20
size_t getsize(float *ptr);
int main(void)
{
float array[size];
printf("the number of bytes in the array is %u""\nthe number of bytes returned bt getsize is %u\n",sizeof(array),getsize(array));
}//end main
size_t getsize(float *ptr)
{
return sizeof(ptr);
}
運算出來the number of bytes in the array is 80為什麼, float為啥是4  float array[size]--4*20

另外%p是將16禁制列印出來?

加下面這兩行下去跑，看結果應該就能了解了

代碼: [選擇]

printf("float size: %lu, float* size: %lu\n",sizeof(float), sizeof(float*));
printf("char size: %lu, char* size: %lu\n",sizeof(char), sizeof(char*));

[gcobt44292]

不太懂 size不是設20嗎float*size=4?? 能稍加解釋一下嗎
課本解釋說:array宣告20元素,這台電腦float變數占用4位元組?

[Yamaka]

不太懂 size不是設20嗎float*size=4?? 能稍加解釋一下嗎
課本解釋說:array宣告20元素,這台電腦float變數占用4位元組?

上面那兩行跑出來的結果還看不懂嗎?! = =||

[gcobt44292]

喔~~懂了 是float浮點數 是4?

[gcobt44292]

還是不太懂